The school colors are blue and yellow, so if amira wants to add yellow rectangles on the left and right sides of the blue rectangle. the yellow rectangles will each be 3/4 yard wide and the same height as the blue rectangle. what will be the total are of the two yellow rectangles?

I encountered this question before. It lacks pertinent information. 

Amira is painting a rectangular banner 2 ¼ yards wide on a wall in the cafeteria. The banner will have a blue background. Amira has enough blue paint to cover the 1 ½ square yards of wall.

a)      Find the height of the banner if Amira uses all of the blue paint. Show work.

b)      The school colors are blue and yellow, so if Amira wants to add yellow rectangles on the left and right sides of the blue rectangle. The yellow rectangles will each be 3/4 yard wide and the same height as the blue rectangle. What will be the total area of the two yellow rectangles?

Area of a rectangle = length * width

Area using the blue paint = 1 ½ square yards.

Height = 1 ½ square yards / 2 ¼ yards or  1.5 sq. yds / 2.25 yd = 0.666 yd or 2/3 yd

1 Yellow rectangle: width = ¾ yards ; length = 2/3 yards

Area of yellow rectangle = ¾ yds * 2/3 yds = 6/12 or ½ square yards

Area of the 2 yellow rectangles = ½ square yard * 2 = 1 square yard.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".