What is the center of (x + 1)2 + (y - 3)2 = 9?
question 10 options:
(-1, 3)
(1, 3)
(1, -3)
(-1, -3)

The equation of a circle with center at (h,k) is
(x-h)^2+(y-k)^2=radius^2

given
(x-(-1))^2+(y-3)^2=9
center is (-1,3)

first option

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!