Mr. martin was comparing two random samples of students test scores from his algebra iii 1st and 3rd block classes: test scores from 1st block: 92,84,85,77,60,92,68,88,76,89,94,56 ,72,45,66; mean: ≈ 76.3 standard deviation: ≈ 14.3 test scores from 3rd block: 72,77,84,79,66,74,88,72,73,64,82,85 ,74,74,97; mean: ≈ 77.4 standard deviation: ≈ 8.34 what can mr. martin most accurately conclude between the overall class test scores of 1st and 3rd blocks?

3rd block scores are more consistent than first block scores.

Step-by-step explanation:

Given that Mr. Martin was comparing two random samples of students test scores from his Algebra III 1st and 3rd block classes:

Test scores from 1st block:

92,84,85,77,60,92,68,88,76,89,94,56,72,45,66;

Mean: ≈ 76.3 Standard deviation: ≈ 14.3

Test scores from 3rd block:

72,77,84,79,66,74,88,72,73,64,82,85,74,74,97;

Mean: ≈ 77.4 Standard deviation: ≈ 8.34

Since std deviation is lower in 3rd block, we can say 3rd block scores are consistent.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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step-by-step explanation: