You are throwing darts at a dart board. you have a 1/ 6 chance of striking the bull's-eye each time you throw. if you throw 3 times, what is the probability that you will strike the bull's-eye all 3 times?

a. 5 /136

b. 1/ 216

c. 3/ 233

d. 1/ 100

B.

Step-by-step explanation:

Given: The chances of striking the bull's-eye each time of throw =\frac{1}{6}

Since, if we throe dart on dart board , each event will be independent of the other.

Then, If we throw 3 times, what is the probability that we will strike the bull's-eye all 3 times is given by :-

Hence, the probability that we will strike the bull's-eye all 3 times is .

55? i think maybe

step-by-step explanation:

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer