Which is a counterexample to this conjecture?

the sum of 3 and any other number is an odd number.

a.
3 + 4 = 7

b.
3 + 51 = 54

c.
3 + 58 = 61

d.
3 + 98 = 101

Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.