Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

177,147
88,572
88,575
177,144

First, we need to solve for the common ratio from the data given by using the equation.

a(n) = a(1) r^(n-1)
59049 = 3 r^(10-1)
19683 = r^9
r = 3

Then, we can find the sum by the expression:

S(n) = a(1) ( r^n -1) / 1-r
S(10) = 3 (3^10  -1  ) / 3-1
S(10) =88572

B) 88572

Step-by-step explanation:

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