The equation of line cd is y = 3x − 3. write an equation of a line perpendicular to line cd in slope-intercept form that contains point (3, 1).

a)y = 3x + 0

b)y = 3x − 8

c)y = negative 1 over 3x + 2

d)y = negative 1 over 3x + 0

The equation of the line must be as y=ax+b

a x 3 = -1, 3 is the slope of y=3x-3
so the answer is 
      
c)y = negative 1 over 3x + 2
proof 
it passes on the point A(3, 1),  -1/3(3)+2=-1+2=1
-1/3)x3= -1   the two lines are truly perpendicular

D