The graph represents the heights of two climbers on a climbing wall over a 12-minute time period.
which statement is true about the climbers’ heights?
brynn was resting at a constant climbing height when abby’s climbing height was decreasing.
abby’s climbing height was decreasing when brynn’s climbing height was increasing.
the heights of both climbers increased, then decreased, with no rest at a constant height.
both climbers rested on the wall at a constant height for 2 minutes.

The graph represents the heights of two climbers on a climbing wall over a 12-minute time period. Consider each graph separately.

Brynn's graph. The height was increasing from the start to the 5th minute. Then Brynn was resting 2 minutes at a constant climbing height, then the   height was decreasing from the 7th minute to the 10th minute.

Abby's graph. The height was increasing from the start to the 4th minute. Then Abby was resting 2 minutes at a constant climbing height, then the   height was again increasing from the 6th minute to the 8th minute and then the height was decreasing from the 8th minute to the 12th minute.

First option is false, becuse actually Abby was resting from 4th to 6th minutes and from 4th to 5th minute Brynn was still climbing.

Second option is false, because Abby’s climbing height starts decreasing later than Brynn's climbing height starts.

Third option is false, because both Brynn and Abby has a rest.

Fourth option is true, because both climers had a 2-minute rest.

correct choice is D

42

step-by-step explanation:

256/6=42

45.36 feet per second.

step-by-step explanation:

to find the most accurate determination for the number of feet per second tyrone traveled on his way to work let us convert miles to feet and minutes to seconds.

1 mile = 5280 feet.

1 minute = 60 seconds.

now we will divide 158400 by 3492 to find the most accurate determination for the number of feet per second tyrone traveled on his way to work.

therefore, tyrone traveled on his way to work at the rate of 45.36 feet per second.