Find the solution of this system of equations. seperate the x and y values with a comma.
x=-2+y
-16x-3y=-25

-16 ( -2 +y) - 3y= -25
32 -16y -3y = -25
32 - 19y = -25
-32. -32

-19y =-57
y=3

We are given 'x' in the first equation.
x = -2 + y
Now we can substitute -2 + y into the second equation.
-16 (-2 + y) - 3y = -25

Distributing -16 will get:
32 - 16y - 3y = -25
and now we can simplify it and find 'y'
32 - 19y = -25
-19y = -57
y = 3

Then we can substitute 3 for 'y' in the original equation.
x = -2 + 3 ---> x = 1
(1,3) is the answer

To check these answers we just substitute 'x' and 'y' into both equations.
1) 1 = -2 + 3 True

2) -16(1) - 3(3) = -25
-16 - 9 = -25 True

Hope I helped you!

Look i don’t know the answer to this but someone else will so just wait a little bit longer