Can someone check this?
2x^2 + 50 = β20x
2x^2 + 20x + 50 = 0
2(x^2 + 10x + 25)...
Mathematics, 17.10.2019 14:10 maritzamartinnez
Can someone check this?
2x^2 + 50 = β20x
2x^2 + 20x + 50 = 0
2(x^2 + 10x + 25) = 0
2(x + 5)(x + 5) = 0
(x + 5)(x + 5) = 0
x + 5 = 0 or x + 5 = 0
x = β 5, x = β 5
the solution set is
{β5}.
Answers: 2
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