Suppose $6,500 is divided into two bank accounts. one account pays 10% simple interest per year and the other pays 4.6%. after two years there is a total of $1000 in interest between the two accounts. how much was invested into the bank account that pays 4.6% simple interest (rounded to the nearest cent)?

Interest1+interest2=1000
case 1
principal= x
rate of interest=10/100
time= 2 years
i=p*t*r/100
(10*x*2)/100
20x/100
case 2
principal= 6500 -x
rate of interest = 4.6/100
time =2 years
i=p*t*r/100
(6500-x*2*4.6)/100
(6500-x)*9.2/100
61800-9.2x/100
interest1+interest2=1000
20x/100+61800-9.2x/100 =1000
61800-9.2x+20x/100=1000
61800+10.8x=1
x=(1 -61800)/10.8
x= 38200/10.8
x=$ 3,537.04
6500 -x = 6500-3,537.04
=$2962.96
if rounded to the nearest cent the answer is
x=$3,537.00
6500-x=$2963.00

Just a second zzz