The height, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d(t) from t = 3 to t = 6 represent?

the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.

the coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds.

the coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.

Option C

Step-by-step explanation:

Given : A coin dropped from a tall building is modeled by the equation where,  d is the distance traveled at time t seconds and t equals the time in seconds.

To find: The average rate of change of d(t) from t = 3 to t = 6

For t = 3 :

For t=6 :

The difference of distance traveled between t=3 and t=6 seconds.

Now, we find the average speed :

Therefore, Option C - The coin falls down with an average speed of 44.1 meter from 3 seconds to 6 seconds.

this is a very good question

step-by-step explanation:

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