The figure is drawn on centimeter grid paper. find the perimeter of the shaded figure to the nearest tenth.
a. 17.6 cm
b. 10.8 cm
c. 15.6 cm
d. 18.0 cm

Option A. 17.6 cm

Step-by-step explanation:

Now if we redraw the figure as figure attached.

Rectangle ABCD can be divided in three triangles

Now we apply Pythagoras theorem in ΔAED to get the measure of side DE

DE = √(7² + 3²) = √(49+9) = √58 = 7.62 cm

Now we apply Pythagoras theorem in ΔCDF to get the measure of side DF

DF = √(4²+ 3²) = √(16+9) = 5 cm

Now we calculate the perimeter of EBFD

Perimeter of the shaded figure = mEB + mBF + mFD + mDE

                                                   = 1 + 4 + 5 + 7.6 = 17.6 cm

Therefore Option A. 17.6 is the answer.

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step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}