If f(1)=10 and f(n)=−3f(n−1) then find the value of f(6).

Basically, recursive thingummy

f(1)=10
f(2)=-3f(2-1)=-3f(1)=-3(10)=-30
f(3)=-3f(3-1)=-3f(2)=-3(-30)=90
f(4)=-3f(4-1)=-3f(3)=-3(90)=-270
f(5)=-3f(5-1)=-3f(4)=-3(-270)=810
f(6)=-3f(6-1)=-3f(5)=-3(810)=-2430

we can actually define this as

so 6th term is

6th term is -2430