8. write the equation of a line that is perpendicular to the given line and that passes through the
given point.
y – 3 = 8/3(x + 2); (–2, 3)
(1 point)
a. y + 3 = -3/8 (x – 2)
b. y – 3 = –3/8 (x + 2)
c. y – 2 = –3/8 (x + 3)
d. y + 3 =3/8 (x – 2)

, i have no idea where to even start

Y - 3 = 8/3(x + 2)...the slope here is 8/3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -3/8

y - y1 = m(x - x1)
slope(m) = -3/8
(-2,3)x1 = -2 and y1 = 3
now we sub
y - 3 = - 3/8(x - (-2)...not done yet
y - 3 = -3/8(x + 2) <===