Log(x+3)(2x+3)+log(x+3)(x+5)=2

log(x-3)+log(x) = 2 + log(x+2) 

log[(x-3)x] - log(x+2) = 2

log[(x^2-3x)/(x+2)] = 2

(x^2-3x)/(x+2) = 2^2


x^2-3x = 4x+8
x^2 - 7x - 8 = 0
Factor:
(x-8)(x+1) = 0
Positive solution:
x = 8

The answer would be b