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what is the equation in point slope form of the line that passes through the point (1, –2) and has a slope of 3?

y−2=3(x+1)

y+2=3(x−1)

y+1=3(x−2)

y−1=3(x+2)

General form of the line equation is: y= mx + c 
where m is the slope and c is the constant 
the slope here is given and equal to 3 
so, m= 3 
y= 3x +c 
to get the constant c, substitute with the point in this equation 
y= -2 & x = 1 
-2 = 3*1 + c 
c = -5 
then the equation of the line is y = 3x -5 
y = 3x -3 -2 
y +2 = 3(x-1) 
the answer is (B)