Given: abcd is a rhombus ac = 3x + 1, and bd = 4x + 2 the area of a rhombus can be represented by the formula a= 1 2 d1d2 where d1 and d2 are diagonals of the polygon. which expression represents the area of the rhombus? \

A = 6x² + 5x + 1

Step-by-step explanation:

The area of a rhombus is where d₁ is one diagonal and d₂ is the other diagonal.

If we have the rhombus ABCD, the diagonals are AC and BD.

The problem tells us that AC = 3x + 1 and BD = 4x + 2

Substituting this in our formula for the area and simplifying as much as we can (by factorizing) we get:

Therefore the area is A = (3x + 1) (2x + 1). If you want to solve the parenthesis you'd get A = 6x² + 5x + 1

the circle one