Can someone (preferably one of the long-term tutors) check my answers:
researchers trap 23 devils, and find that 18 of them are infected. provide an estimate of disease prevalence.
p-hat = (18/23)=0.783 part ii: assuming the same disease prevalence from above.
if they trap 2 devils, what’s the probability that they will get an appropriate pair (i. e. one uninfected female and one uninfected male)?
i used combinatorics: 23 total, 18 infected and 5 uninfected prevalence: 0.783 5c2/23c2 = 10/253 = 0.0395 (0.) = .0309 or 3.1% just need to make sure i'm on the right track. for your .

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