How do i calculate:

((6 x y−2 x y)−x2y2)+10 x y

6xy−2xy−x2y2+10xy=6xy+−2xy+−x2y2+10xy=6xy+−2xy+−x2y2+10xy=(−x2y2)+(6xy+−2xy+10xy)=−x2y2+14xy
=−x2y2+14xy

4xy-x2y2=-10xy
-x2y2=-14xy
x2y2=14xynd class

i think its the answer it can be solved after but it will only get complicated it depends on yor chapter a

Hey, can you post the problem?