What are the first four terms of the sequence defined recursively below
a^1=5
a^n=(-1)^n+3a^n-1 +2

At n = 2
a₂ = (-1)² + 3a₂₋₁ + 2
a₂ = 1 + 3a₁ + 2
a₂ = 1 + (3)(5) + 2
a₂ = 18

At n = 3
a₃ = (-1)³ + 3a₃₋₁ + 2
a₃ = -1 + 3a₂ + 2
a₃ = -1 + (3)(18) + 2
a₃ = 55

At n = 4
a₄ = (-1)⁴ + 3a₄₋₁ + 2
a₄ = 1 + 3a₃ + 2
a₄ = 1 + (3)(55) + 2
a₄ = 168

The first four terms are 5, 18, 55, 168

The solution to the system of equations (-2,2)