3questions will upvote
1.write the equation of a line with a slope of 3 and a y-intercept of 1.

y = x + 3
y = 3x + 1
3x + y = 1
x + 3y = 1
2.write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form.

y – 1 = 2(x – 3)
y – 3 = 2(x – 1)
x – 1 = 2(y – 3)
x – 3 = 2(y – 1)
3.write the equation of the line that passes through (–2, 6) and (2, 14) in slope-intercept form.

y = 2x – 2
y = 2x + 10
y = 0.5x + 7
y = 0.5x – 4

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

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step-by-step explanation:

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the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9