Using hooke's law, f spring=k delta x, find the distance a spring with an elastic constant of 4 n/cm will stretch if a 2 newton force is applied to it.
a.) 2 cm
b.) 1/2 cm
c.) 4 cm
d.) 8 cm

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx  

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:

simplify by 2  

B.) 1/2 cm

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step-by-step explanation: