Gina invests $1,677 in an account paying 8.61% simple interest annually. how much interest has gina gained after six years? a. $668.65 b. $240.65 c. $866.34 d. $2,543.34

Option (c) is correct.

The interest gained by Gini in 6 years is $ 866.34

Step-by-step explanation:

Given: Gina invests $1,677 in an account paying 8.61% simple interest annually for 6 years.

We have to calculate the interest gained by Gina in 6 years.

Using formula for simple interest

Where,

S.I = simple interest

P is principal

R is interest rate

T is time  

Given : P = $ 1677

R = 8.61%

T = 6 years

Substitute, we get,

Simplify, we get,

S.I. = $ 866.3382

Rounding off to nearest hundred  we get, Interest is $866.34

Thus, the interest gained by Gini in 6 years is $ 866.34

i would need to see the dot plot : )

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!