Find the point on the hyperbola xy=8 that is closet to the point (3,0)

Use distance formula to get a distance function in terms of x representing the distance from a point on curve (x,y) to point (3,0)



y = 8/x


Minimize the function by setting derivative equal to 0.

Simplify and solve for x

This becomes a 4th degree polynomial, you can use graphing calculator to find zeros.
Also intuitively you can recognize that 64 = 4^3, so if x=4 you get 
1 = 1

Therefore x=4 is a solution, substituting give  y =2

Your answer should be “c” mark me brainliest