What is the average rate of change of the function below on the interval from x = 0 to x = 2? f(x)=250(0.5)^x

-93.75

62.5

0

-0.25

Rate of change is for (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)

y1=f(x1)
y2=f(x2)

raate of change=(f(x2)-f(x1))/(x2-x1)

find f(x2) and f(x1)

the x1=0
x2=2

f(0)=250 (remember that x^0=1)
f(2)=62.5

average rae of change is (62.5-250)/(2-0)=187.5/2=-93.75
answer is -93.75

Hello! mark me brainliest
answer:
congruent segments
step-by-step explanation:
congruent segments. take a line, cut it in half, superipose one half over the other half; you'll have congruence.

Yes, that is the correct formula. to solve this problem given the number of years, plug in the number of years for t and plug the whole thing into the