Ican't seem to work out this problem using quadratic formula. how do i do this problem?

Iwill make brain if you me correctly fill this out needs due today pls and send it back to me (click the link and you will get it)

When the solutions to each of the two equations below are graphed in the xy-coordinate plane, the graphs of the solutions intersect at two places. write the y-cordninates of the points of intersection in the boxes below in order from smallest to largest. y=2x y=x^2-3

Find the values of y: 3y^3(y^2+ 2/3y)=0