a movie theater has 400 seats. tickets at the theater cost $8 for students, $10 for adults, and $7 for senior citizens. on a night when all the seats were sold, the theater made $3,535 from ticket sales. if the number of adult tickets sold was 10 less than the number of student and senior tickets combined, how many senior tickets were sold?

55 senior tickets
150 senior tickets
195 senior tickets
255 senior tickets

Option A is the answer.

Step-by-step explanation:

Let the tickets of students be represented by 's'

Let the tickets of adults be represented by 'a'

Let the tickets of senior citizens be represented by 'c'

Given is :

A movie theater has 400 seats.

             .....(1)

Tickets at the theater cost $8 for students, $10 for adults, and $7 for senior citizens, a total of $3535 was made.

       .....(2)

Also given - If the number of adult tickets sold was 10 less than the number of student and senior tickets combined.

              .....(3)

Putting the value from (3) in (1)

               .....(4)

Again putting (3) in (2)

            .....(5)

Now solving (4) and (5)

Multiplying (4) by 9 and subtracting (5) from (4)

      ....(4)

18c-17c=3690-3535

c=55

So, there are 55 senior citizens tickets.

7

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2