Given the following linear function, sketch the graph of the function and find the domain and range. f(x)=2/3x-3

(a) Graph : In attachment

(b) Domain: (-∞,∞)

(c) Range: (-∞,∞)

Step-by-step explanation:

Given:

It is a linear function.

For sketch:

Put x=3 into f(x) to get y

f(3) = 2 - 3 = -1

Point (3,-1)

Put x=-3 into f(x) to get y

f(3) = -2 - 3 = -5

Point (-3,-5)

Plot the points on graph and join the points. Please find the attachment.

For domain:

It is input value of x where function is well defined.

Domain: All real number

For range:

It is output value of y.

Range: All real number.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%