Triangle xyz is shown on the coordinate plane below.

if triangle xyz is reflected across the line y = 1 to create triangle x'y'z', what is the ordered pair of x'?
(-4, 5)

(-2, 5)

(4, -3)

(4, -5)

The x coordinate of X and X' has to be the same. The coordinates of X is (4,5) so its distance to y=1 is 5 - 1 = 4. The distance from X' to y=1 must also be 4. The distance from -3 to 1 is 4. So, the answer for the given question above is (4,-3). I hope this helps.