If (x+1)(x+4) -(x-2)=0 what is the value of x?
a: -1
b: - 1/4
c: 0
d: 1/4
e: 1

(x+1)(x-4)-(x-2) = 0
x²-4x+x-4-x+2 = 0
x²-4x-2 = 0
/\ = (-4)² - 4*1*(-2)
/\ = 16 + 8
/\ = 24
x = (-(-4)+/- \/24) / 2
x = (4+/-\/4*6)/2
x = (4+/-2\/6)/2
x = 2+/-\/6
x' = 2+\/6
x" = 2-\/6