A community swimming pool has a deep end and a shallow end. The volume of water in the deep end can be represented by (2x2+12x+10) ft3 and the volume of the water in the shallow end can be represented by (4x2−100)ft3. Write the equivalent expression ("simplified") that represents the total volume of the water in the pool in ft3.

The total volume of water in the pool  = ( 6x^3 + 12x^2 - 90x ) ft^3

Step-by-step explanation:

The volume of water in the deep end = (2x^3 + 12x2 + 10x) ft^3

The volume of water in the shallow     =  (4x^3 -100x) ft^3

The total volume of water in the pool  = (2x^3 + 12x2 + 10x)  +  4x^3 -100x)

                                                              = ( 6x^3 + 12x^2 - 90x ) ft^3

answer: 10 turtles

step-by-step explanation: as turtles have four legs so 4.10=40 therefore birds are 4 which sue counted