A sequence defined by the rule f(n)=4f(n-1)+2.if f(1)=3 then find f(4)=?

f(4) = 6

Step-by-step explanation:

Given the rule f(n) = 4f (n - 1) + 2 where f(1) = 3, f(n) is just a fancy way to name the variable y. As you've seen before, there are equations that are usually y equals x and something. For example:

y = mx + b

is the same thing as

f(n) = y = mn + b.

It might be that you have multiple of the same equation where f(n) and f(x) have two different outcomes.

The f(n) part (bolded) is the "x variable" in this equation. So in f(1), n = 1.

f(n) = 4f (n - 1) + 2

f(n) = (4fn - 4f) + 2

f(n) = (n) + 2

f(1) = 1 +2

3 = 3

Now do the same thing for f(4):

f(n) = 4f (n - 1) + 2

f(n) = (4fn - 4f) + 2

f(n) = (n) + 2

f(4) = 4 + 2

f(4) = 6

a ruler? idk

step-by-step explanation:

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: