Please help ! and thank you in advance The function f'(x) = cos(In x) is the first derivative of a twice differentiable function, f(x).

On the interval 0<x<10 , find the x-values where f(x) has a relative minimum? Justify your answer ​

same as above

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2