Can someone give steps to the solution for this problem : Find the 6th term of the arithmetic sequence x-3x−3, -x-5−x−5, -3x-7, ...−3x−7,...

2x−1−7−x3x−3 2 x − 1 − 7 − x 3 x − 3. =2x−1−7−x3(x−1) = 2 x − 1 − 7 − x 3 ( x − 1 ). =2.3(x−1).3−7−x3(x−1) = 2.3 ( x − 1 ) .3 − 7 − x 3 ( x − 1 ).

Step-by-step explanation:

x 3x-1 = 5 (x-1) -2 (7-2x). 3x − 1 = 5 (x − 1) −2 (7−2x) 3 x - 1 = 5 (x - 1) - 2 (7 - 2 x). Since x x is on the right side of the equation, we swap it so it is on the left side of the equation

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!