HELP PLZ DUE RN BRAINIEST TO WHOEVER RIGHT

x = 11, -1

Step-by-step explanation:

First, let's identify what the quadratic formula is:

x = [-b ± √(b² - 4(a)(c))] / 2

Our equation is written in standard form:

ax² + bx + c = 0

x² - 10x - 11 = 0

Let's plug in what we know.

x = [-(-10) ± √((-10)² - 4(1)(-11))] / 2

Evaluate the exponent.

x = [-(-10) ± √(100 - 4(1)(-11))] / 2

Simplify the negatives.

x = [10 ± √(100 - 4(1)(-11))] / 2

Multiply.

x = [10 ± √(100 + 44)] / 2

Simplify the parentheses.

x = [10 ± √(144)] / 2

Simplify the radical (√)

x = [10 ± 12] / 2

Evaluate the ±.

x = [10 + 12] / 2

x = [22] / 2

x = 11

or

x = [10 - 12] / 2

x = [-2] / 2

x = -1

Your answers are x = 11, -1

Hope this helps!

b

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v