A company is going to make an oil container in the shape of a cylinder. As shown below, the container will have a height of 5m and a radius of 3m. The container will be made from steel (including its top and bottom). If the steel costs $24 for each square meter, how much will the steel cost in total? If necessary, refer to the list of geometry formulas. For your calculations, do not round any intermediate steps, and use the π button on the ALEKS calculator. Round your answer to the nearest cent.

1,172.3 cm³

Step-by-step explanation:

Find the volume of one rod, then divide the total volume of steel used by the volume of one rod.  The volume of one rod is

V = (πd²/4)h

d = 4 cm

h = 20 cm

Plugin the numbers and get V in cm³, then divide the given total volume of 28,134.4 cm³ by V.  If the result is not an integer, then round down.

Add

20 + 4 = 24

Then

28,134.4 ÷ 24 = 1172.26

Rounded to the nearest 0.1 or  the Tenths Place = 1,172.3

Therefore, 1,172.3 rods will be made per hour.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2