Two baseball teams meet in a playoff series at the end of the regular season. Team A won 55 of 81 games played in its home stadium during the regular season, while Team B won 48 of 81 games played in its home stadium. The first two games of the series will be played in Team A's home stadium, the next two games in Team B's home stadium. In the absence of any other information, which expression is equal to the probability that Team A will win the first four games in a row?

Assuming the statistics are independent of the visiting team, then probability of team A winning in home turf is P(A)=55/81, and winning as a visitor of team B is P(B)=(81-48)/81=33/81.

So winning all four games,

P = P(A)*P(A)*P(B)*P(B)

2.

Total volume = 9³ cm³ = 729 cm³.

Side of each of 3 new cubes

= cube root of (729 cm³ /3) cm

= cube root of (243) cm.

3.

Total number of ways to pick 4 balls out of 9

= C(9,4) = 9!/(4!5!)=126

Total number of ways to pick 4 blue balls = C(4,4) = 1

total number of ways to pick 4 red balls

= C(5,4) = 5

Number of ways of not choosing 4 red nor 4 blue = (126 - 1 - 5) = 120

Probability of not choosing 4 balls of the same colour is therefore ...?

its   c, f, a

step-by-step explanation: