A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form? –n2 + 3n + 5
n2 + 6n + 1
2n2 + 6n – 1
3n2 + 5

n^2 + 6n + 1

Step-by-step explanation:

Firstly, we have to evaluate AB

What we have to do is to multiply A and B

We have this as;

n(2n + 6) = 2n^2 + 6n

Now, we have to subtract the value of C from here and that is;

(2n^2 + 6n) - (n^2 - 1)

2n^2 + 6n - n^2 + 1

= 2n^2 -n^2 + 6n + 1

= n^2 + 6n + 1

B

Step-by-step explanation:

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step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1