find An Equation Of The Line Containg(3,-4) and Having slope -2.If This Line Contain The Points (a,8) and (5,b) find a and b​

equation: y=-2x+2

a=-3

b=-8

Step-by-step explanation:

we need to find the equation of the line containing the point (3,-4) and has the slope (m) of -2

slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

we can plug what we know into the equation:

y=-2x+b

we need to find b though

since the point will pass through the point (3,-4) we can subsitute it into the equation to find b

-4=-2(3)+b

-4=-6+b

2=b

the y intercept is 2

so the equation is y=-2x+2

the line also contains the points (a,8) and (5,b)

first, let's find a

a is the x value of the point

we know the value of y (8)

substitute y as 8 and solve for x

8=-2x+2

subtract

6=-2x

-3=x=a

so a is -3

now find b

b is the y value of the point

we know the x value (5)

substitute x as 5 and solve for y

y=-2(5)+2

y=-10+2

y=-8=b

so b is -8

hope this helps!

3x^3-x^2+6x-9