An observer (O) is located 500 feet from a school (S). The observer notices a bird (B) flying at a 39° angle of elevation from his line of sight. How high is the bird flying over the school? You must show all work and calculations to receive full credit.

404.89ft

Step-by-step explanation:

Given the following

Distance of observer from the school  = 500ft  (adjacent)

Angle of elevation = 39degrees

Required

Height of the school (H) (opposite)

Using the SOH CAH TOA identity

tan theta = opp/adj

tan39 = H/500

H = 500tan39

H = 404.89ft

Hence the bird is flying at 404.89ft over the school

Step-by-step explanation:

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm

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step-by-step explanation:

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