Algebra 1: 6.06 Scatterplot and Line of Best Fit PART 1: MEASUREMENTS - Data Record (Use data given below or create your own)
Name
Arm Span in Inches (x)
Height in Inches (y)
Student 1
65
66
Student 2
58
57
Student 3
61.5
61
Student 4
75
75
Student 5
61.75
62
Student 6
64
63
Student 7
71
68
Student 8
77
78
Student 9
65
66
Student 10
44
48
Yourself
80
79
Family/Friend
62
61

Part 2: REPRESENTATION OF DATA WITH PLOTS

Using graphing software create a scatter plot of your data.

Make sure to label the x- and y-axis and choose a domain and range that fits your data table.

Draw the line of best fit

*If doing by hand, you can take a picture of your graph and insert into your document
PART 3: QUESTIONS

Which variable did you plot on the x-axis, and which variable did you plot on the y-axis? Explain why you assigned the variables in that way.
I plotted the arm span on the x axis and the height on the Y axis. I do not have an explanation as to why, that was just the default so I kept it.
Write the equation of the line of best fit using the slope-intercept formula y = mx + b. (Refer to Lesson- PAGE 3, the “Marathon” example, to determine the “Determine the Line of Best Fit” tab for help on choosing two points, finding slope and writing the equation of your best fit line) Show all your work, including the points used to determine the slope and how the equation was determined.

What does the slope of the line represent within the context of your graph? What does the y-intercept represent?

Bonus: Test the residuals of two other points to determine how well the line of best fit models the data.

Use the line of best fit to help you to describe the data correlation. (positive, negative, or no correlation)

According to your line of best fit (equation) that you found in, Question 2, approximate how tall is a person whose arm span is 66 inches? Show work using your equation in Question 2 to support.

According to your line of best fit, what is the arm span of a 74-inch-tall person? Show work using your equation in Question 2 to support.