The width of a box is two-third of its length and height is one-third of its length. If the volume of the box is 1296 m3,
ind the area of base of the box.​

216m² is your answer

Step-by-step explanation:

given

width [b]=2/3 ×l

length [l]=l

height [h]=1/3 l

we have

volume of cuboid =l×b×h

1296m³=l×2/3×l×1/3×l

1296m³=2/9×l³

l³=1296×9/2=5832

l³=18³

length [l]=18m

breadth [b]=2/3×18=12m

area of base of box =l×b=18×12=216m²

a: 1/6, j: 1/4

step-by-step explanation: you are welcome