Given: Quadrilateral ABCD has vertices A(-5,6), B(6,6), C(8,-3), and D(-3,-3). Which of the following ways can prove that quadrilateral ABCD is a parallelogram but is neither
a rhombus nor a rectangle?
A:The diagonals are congruent and perpendicular.
B:The midpoints of the diagonals are the same, the diagonals are not congruent, and
two adjacent sides are not congruent.
C
The four sides are congruent and the diagonals are perpendicular.
D
The slopes of the adjacent sides are negative reciprocals of one another and the
midpoints of the diagonals are the same.