A basketball game a team made 52 successful shots they were a combination of 1- and 2- point shots the team scored 86 points in all write and solve a system of equations to find the number of each type of shot

15

Step-by-step explanation:

x = one point shots

y = two point shots

1) Setup your equations.

x + y = 52

x + 2y = 89

2) Isolate a variable.

x = 52-y

3) Plug in.

(52-y) + 2y = 89

52 +y =89

y=37

4) Solve for x.

x = 52 -37

x=15

5) Check your answer.

15 + 2(37) = 89

15+74=89

89=89

37+15 = 52

52=52

x = one point shots

y = two point shots

1) Setup your equations.

x + y = 52

x + 2y = 89

2) Isolate a variable.

x = 52-y

3) Plug in.

(52-y) + 2y = 89

52 +y =89

y=37

4) Solve for x.

x = 52 -37

x=15

5) Check your answer.

15 + 2(37) = 89

15+74=89

89=89

37+15 = 52

52=52

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.