Find the sum of 4x^2+3x+2 and 7x^2+7 x+3

11x² + 10x + 5

Step-by-step explanation:

= (4x² + 3x + 2) + (7x² + 7x + 3)

= 4x² + 3x + 2 + 7x² + 7x + 3

= 4x² + 7x² + 3x + 7x + 2  + 3

= 11x² + 10x + 5

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: