Two processes in a manufacturing line are performed manually: operation A and operation B. A random sample of 50 different assemblies using operation A shows that the sample average time per assembly is 8.05 minutes, with a population standard deviation of 1.36 minutes. A random sample of 38 different assemblies using operation B shows that the sample average time per assembly is 7.26 minutes, with a population standard deviation of 1.06 minutes. Required:
For α = 0.10, is there enough evidence in these samples to declare that operation A takes significantly longer to perform than operation B?

3.06

Step-by-step explanation:

The correct answer is - 3.06

Reason -

For sample A :

mean, = 8.05          

Standard deviation, = 1.36          

Size, = 50          

For sample B :

mean, = 7.26          

Standard deviation, = 1.06          

Size, = 38

Now,

-  = 8.05 - 7.26 = 0.79

Standard deviation error, SE = √(²/ + ²/)  = 0.2580

Now,

Z-statistic = ( - )/ SE

                = 0.79/0.2580

                = 3.06

⇒Z-statistic = 3.06

i think the length is 12 and the width is 17

pla·gia·rism

/ˈplājəˌrizəm/

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noun

the practice of taking someone else's work or ideas and passing them off as one's own.

step-by-step explanation: