A scientist claims that 6% of viruses are airborne. (a) If the scientist is accurate, what is the probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8%? Round your answer to four decimal places.

Probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8% is 0.9545.

Step-by-step explanation:

For the given population the distribution of air-borne viruses is given as 6%. Now for this the value of Z score is given as

Here

So the Z score is given as

For this the score, the value of probability is calculated from the table as below:

Here value of p(Z<-1.6955) is given as 0.0455

the answer is y = 11.54

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