F(x)=-x^2-4x+12
find the minimum/maximum value

Maximum Value / Vertex : (-2,16)

Step-by-step explanation:

Since the value of a is negative, we will solve for the maximum.

Finding the x-value of the vertex of the parabola is x=-b/2a:

x=-(-4)/2(-1)

x=4/-2

x=-2

Now if we plug x=-2 into the function, we'll get our y-value for the vertex:

f(-2)=-(-2)^2-4(-2)+12

f(-2)=-(4)+8+12

f(-2)=-4+20

f(-2)=16

So the vertex of our parabola is (-2,16) which is our maximum value

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!