A show pony weighs at least 900 pounds. After a recent weigh in, the owner of a show pony amended the diet of his pony, increasing the animal's caloric intake, with the hope that the pony would gain weight to be shown in a few months. The data shown in the table and scatter plot below represents the pony's additional daily caloric intake and recorded weight gain (in pounds) of the show pony over the last ten weeks. Additional Daily Calories Consumed Weight Gained

(in pounds)
1,500 3
1,575 7
1,650 3
1,725 4
1,800 8
1,875 9
1,950 13
2,025 7
2,100 17
2,175 15
Part A: Use the data shown in the table and scatter plot to create an approximate equation for the line of best fit.

Part B: In complete sentences, describe the show pony's weight gain in terms of the units used in the data.

Part C: According to the equation for the best fit line for the data, approximately how much weight would you expect the pony to gain in a week if its additional daily caloric intake for that week is 2,300 calories?

the axial of symmetry

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)